Vote Sharing
In a college election for president, four candidates participated. The total number of votes casted exactly are 963. The winner exceeds the opponents by 53, 79 and 105 votes. How many votes does each individuals should have got?
Answer:
Winner - 300
Runner 1 - 247
Runner 2 - 221
Runner 3 - 195
How to arrive at the solution?
The total number of votes of all candidates equals 963.
Hence,
X + (X-53) + (X-79) + (X-105) = 963
4X - 237 = 963
4X = 1200
X = 300
Therefore, the remaining candidates' votes will be in the order 247(300 - 53), 221(300-79) and 195(300-105).
Answer:
Winner - 300
Runner 1 - 247
Runner 2 - 221
Runner 3 - 195
How to arrive at the solution?
The total number of votes of all candidates equals 963.
Hence,
X + (X-53) + (X-79) + (X-105) = 963
4X - 237 = 963
4X = 1200
X = 300
Therefore, the remaining candidates' votes will be in the order 247(300 - 53), 221(300-79) and 195(300-105).
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