CATS AND DOGS

A dealer bought a number of cats at Rs. 344 each, and a number of dogs at Rs. 265 each. He then discovered that the cats had cost him in all Rs. 33 more than the dogs. Now, what is the smallest number of each that he must have bought?

 Answer:

 Let the amount of cats and dogs be x and y respectively.
We have to solve the indeterminate equation 

344x = 265y + 33. 

On solving this equation, we get x is 252, and y is 327, so that if he buys 252 cats for Rs. 344 a piece, and 327 dogs  for Rs. 265 apiece, the cats will cost him in all Rs. 33 more than the dogs.

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